It cost nearly $100 more for a night out in Austin than it does in San Antonio, according to the study. Credit: Shutterstock /bogdanhoda

Alamo City residents looking for a cheap night out picked the right spot to put down roots. SA is among the cheapest cities in the nation for a night on the town, according to a new study.

An average night out in San Antonio costs about $134.56, landing the Alamo City as the nation’s second-most affordable city to have fun in, according to number crunching by price-monitoring website PriceListo.

PriceListo collected cost-of-living data from every U.S. city with more than 500,000 inhabitants, analyzing the average cost of a cocktail, three-mile cab fare, a bottle of wine and a pint of beer. Researchers also factored in data from hotel site Vio to determine the average nightly rate for a budget hotel to compile its list.

As long as you skip the casino, Las Vegas came in as the most affordable city for a night out at an average cost of $120.76. Oklahoma City followed behind SA with an average of $136.98 for a night out.

Only one other Texas city, Fort Worth, made the top 10, landing at No. 9. There, revelers can expect to drop $172.14 for a night out.

On the other end of the spectrum, San Diego took the title of the most expensive city in the nation for a night on the town. Two other Texas cities, Austin and Houston, took the No. 3 and No. 9 spots, respectively.

A night out in Austin costs nearly $100 more than a night out in San Antonio, according to the analysis.

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Michael Karlis is a multimedia journalist at the San Antonio Current, whose coverage in print and on social media focuses on local and state politics. He is a graduate of American University in Washington,...